# 3D Stress Concentration Analysis for a Notched Plate#

This tutorial is the 3D corollary to the 2D plane example MAPDL 2D Plane Stress Concentration Analysis, but This example verifies the stress concentration factor $$K-t$$ when modeling opposite single notches in a finite width thin plate

First, start MAPDL as a service and disable all but error messages.

from matplotlib import pyplot as plt

# sphinx_gallery_thumbnail_number = 3
import numpy as np

from ansys.mapdl.core import launch_mapdl

mapdl = launch_mapdl(loglevel="ERROR")


## Geometry#

Create a rectangular area with two notches at the top and bottom.

length = 0.4
width = 0.1

notch_depth = 0.04

# create the half arcs
mapdl.prep7()

circ0_kp = mapdl.k(x=length / 2, y=width + notch_radius)
circ_line_num = circ_line_num[2:]  # only concerned with the bottom arcs

# create a line and drag the top circle downward
circ0_kp = mapdl.k(x=0, y=0)
k1 = mapdl.k(x=0, y=-notch_depth)
l0 = mapdl.l(circ0_kp, k1)

# same thing for the bottom notch (except upwards
circ1_kp = mapdl.k(x=length / 2, y=-notch_radius)
circ_line_num = circ_line_num[:2]  # only concerned with the top arcs

# create a line whereby the top circle will be dragged up
k0 = mapdl.k(x=0, y=0)
k1 = mapdl.k(x=0, y=notch_depth)
l0 = mapdl.l(k0, k1)

rect_anum = mapdl.blc4(width=length, height=width)

# Note how pyansys parses the output and returns the area numbers
# created by each command.  This can be used to execute a boolean
# operation on these areas to cut the circle out of the rectangle.
# plate_with_hole_anum = mapdl.asba(rect_anum, circ_anum)
cut_area = mapdl.asba(rect_anum, "ALL")  # cut all areas except the plate

# mapdl.aplot(vtk=True, show_line_numbering=True)
mapdl.lsla("S")
mapdl.lplot(vtk=True, show_keypoint_numbering=True)
mapdl.lsel("all")

# plot the area using vtk/pyvista
mapdl.aplot(vtk=True, show_area_numbering=True, show_lines=True, cpos="xy")

# Next, extrude the area to create volume
thickness = 0.01
mapdl.vext(cut_area, dz=thickness)

# Checking volume plot


## Meshing#

This example will use PLANE183 elements as a thin plate can be modeled with plane elements provided that KEYOPTION 3 is set to 3 and a thickness is provided.

Mesh the plate using a higher density near the hole and a lower density for the remainder of the plate by setting LESIZE for the lines nearby the hole and ESIZE for the mesh global size.

Line numbers can be identified through inspection using lplot

# define a PLANE183 element type with thickness

# ensure there are at 25 elements around the hole
notch_esize = np.pi * notch_radius * 2 / 50
plate_esize = 0.01

# increased the density of the mesh at the notch
# line and area numbers identified using aplot

mapdl.asel("S", "AREA", vmin=1, vmax=1)
mapdl.aplot(vtk=True, show_line_numbering=True)

mapdl.lsel("NONE")
for line in [7, 8, 20, 21]:
mapdl.lsel("A", "LINE", vmin=line, vmax=line)
mapdl.lesize("ALL", notch_esize, kforc=1)
mapdl.lsel("ALL")

# Decrease the area mesh expansion.  This ensures that the mesh
# remains fine nearby the hole
mapdl.mopt("EXPND", 0.7)  # default 1

# mesh several elements through the plate
esize = notch_esize * 5
if esize > thickness / 2:
esize = thickness / 2  # minimum of two elements through

mapdl.esize()  # this is tough to automate
mapdl.et(1, "SOLID186")
mapdl.vsweep("all")
mapdl.eplot(vtk=True, show_edges=True, show_axes=False, line_width=2, background="w")


## Material Properties and Boundary Conditions#

Fix the left-hand side of the plate in the X direction and set a force of 1 kN in the positive X direction.

# This example will use SI units.
mapdl.units("SI")  # SI - International system (m, kg, s, K).

# Define a material (nominal steel in SI)
mapdl.mp("EX", 1, 210e9)  # Elastic moduli in Pa (kg/(m*s**2))
mapdl.mp("DENS", 1, 7800)  # Density in kg/m3
mapdl.mp("NUXY", 1, 0.3)  # Poisson's Ratio

# Fix the left-hand side.
mapdl.nsel("S", "LOC", "X", 0)
mapdl.d("ALL", "UX")

# Fix a few nodes on the left-hand side of the plate in the Y and Z
# direction.  Otherwise, the mesh would be allowed to move in the y
# direction and would be an improperly constrained mesh.
mapdl.nsel("R", "LOC", "Y", width / 2)
mapdl.d("ALL", "UY")
mapdl.d("ALL", "UZ")

# Apply a force on the right-hand side of the plate.  For this
# example, we select the nodes at the right-most side of the plate.
mapdl.nsel("S", "LOC", "X", length)

# Verify that only the nodes at length have been selected:
# assert np.unique(mapdl.mesh.nodes[:, 0]) == length

# Next, couple the DOF for these nodes.  This lets us provide a force
# to one node that will be spread throughout all nodes in this coupled
# set.
mapdl.cp(5, "UX", "ALL")

# Select a single node in this set and apply a force to it
# We use "R" to re-select from the current node group
mapdl.nsel("R", "LOC", "Y", width / 2)  # selects more than one
single_node = mapdl.mesh.nnum[0]
mapdl.nsel("S", "NODE", vmin=single_node, vmax=single_node)
mapdl.f("ALL", "FX", 1000)

# finally, be sure to select all nodes again to solve the entire solution
mapdl.allsel(mute=True)


## Solve the Static Problem#

Solve the static analysis

mapdl.run("/SOLU")
mapdl.antype("STATIC")
mapdl.solve()
mapdl.finish(mute=True)


## Post-Processing#

The static result can be post-processed both within MAPDL and outside of MAPDL using pyansys. This example shows how to extract the von Mises stress and plot it using the pyansys result reader.

# grab the result from the mapdl instance
result = mapdl.result
result.plot_principal_nodal_stress(
0,
"SEQV",
lighting=False,
background="w",
show_edges=True,
text_color="k",
)

nnum, stress = result.principal_nodal_stress(0)
von_mises = stress[:, -1]  # von-Mises stress is the right most column

# Must use nanmax as stress is not computed at mid-side nodes
max_stress = np.nanmax(von_mises)

/opt/hostedtoolcache/Python/3.9.16/x64/lib/python3.9/site-packages/pyvista/plotting/tools.py:622: PyVistaDeprecationWarning: The usage of parse_color is deprecated in favor of the new Color class.
warnings.warn(


## Compute the Stress Concentration#

The stress concentration $$K_t$$ is the ratio of the maximum stress at the hole to the far-field stress, or the mean cross sectional stress at a point far from the hole. Analytically, this can be computed with:

$$\sigma_{nom} = \frac{F}{wt}$$

Where

• $$F$$ is the force

• $$w$$ is the width of the plate

• $$t$$ is the thickness of the plate.

Experimentally, this is computed by taking the mean of the nodes at the right-most side of the plate.

# We use nanmean here because mid-side nodes have no stress
mask = result.mesh.nodes[:, 0] == length
print("Far field von mises stress: %e" % far_field_stress)
# Which almost exactly equals the analytical value of 10000000.0 Pa

Far field von mises stress: 9.997885e+05


Since the expected nominal stress across the cross section of the hole will increase as the size of the hole increases, regardless of the stress concentration, the stress must be adjusted to arrive at the correct stress. This stress is adjusted by the ratio of the width over the modified cross section width.

adj = width / (width - notch_depth * 2)

# The stress concentration is then simply the maximum stress divided
# by the adjusted far-field stress.
print("Stress Concentration: %.2f" % stress_con)

Stress Concentration: 1.60


## Batch Analysis#

The above script can be placed within a function to compute the stress concentration for a variety of hole diameters. For each batch, MAPDL is reset and the geometry is generated from scratch.

Note

This section has been disabled to reduce the execution time of this example. Enable it by setting RUN_BATCH = TRUE

RUN_BATCH = False

# The function to compute the batch analysis is the following:

def compute_stress_con(ratio):

notch_depth = ratio * width / 2

mapdl.clear()
mapdl.prep7()

# Notch circle.
circ0_kp = mapdl.k(x=length / 2, y=width + notch_radius)
circ_line_num = circ_line_num[2:]  # only concerned with the bottom arcs

circ0_kp = mapdl.k(x=0, y=0)
k1 = mapdl.k(x=0, y=-notch_depth)
l0 = mapdl.l(circ0_kp, k1)

circ1_kp = mapdl.k(x=length / 2, y=-notch_radius)
circ_line_num = circ_line_num[:2]  # only concerned with the top arcs

k0 = mapdl.k(x=0, y=0)
k1 = mapdl.k(x=0, y=notch_depth)
l0 = mapdl.l(k0, k1)

rect_anum = mapdl.blc4(width=length, height=width)
cut_area = mapdl.asba(rect_anum, "ALL")  # cut all areas except the plate

mapdl.allsel()
mapdl.vext(cut_area, dz=thickness)

notch_esize = np.pi * notch_radius * 2 / 50
plate_esize = 0.01

mapdl.asel("S", "AREA", vmin=1, vmax=1)

mapdl.lsel("NONE")
for line in [7, 8, 20, 21]:
mapdl.lsel("A", "LINE", vmin=line, vmax=line)

mapdl.ksel("NONE")
mapdl.ksel(
"S",
"LOC",
"X",
length / 2 - notch_radius * 1.1,
length / 2 + notch_radius * 1.1,
)
mapdl.lslk("S", 1)
mapdl.lesize("ALL", notch_esize, kforc=1)
mapdl.lsel("ALL")

mapdl.mopt("EXPND", 0.7)  # default 1

esize = notch_esize * 5
if esize > thickness / 2:
esize = thickness / 2  # minimum of two elements through

mapdl.esize()  # this is tough to automate
mapdl.et(1, "SOLID186")
mapdl.vsweep("all")

mapdl.allsel()

# Uncomment if you want to print geometry and mesh plots.
# mapdl.vplot(savefig=f'vplot-{ratio}.png', off_screen=True)
# mapdl.eplot(savefig=f'eplot-{ratio}.png', off_screen=True)

mapdl.units("SI")  # SI - International system (m, kg, s, K).

mapdl.mp("EX", 1, 210e9)  # Elastic moduli in Pa (kg/(m*s**2))
mapdl.mp("DENS", 1, 7800)  # Density in kg/m3
mapdl.mp("NUXY", 1, 0.3)  # Poisson's Ratio

mapdl.nsel("S", "LOC", "X", 0)
mapdl.d("ALL", "UX")

mapdl.nsel("R", "LOC", "Y", width / 2)
mapdl.d("ALL", "UY")
mapdl.d("ALL", "UZ")

mapdl.nsel("S", "LOC", "X", length)
mapdl.cp(5, "UX", "ALL")

mapdl.nsel("R", "LOC", "Y", width / 2)  # selects more than one
single_node = mapdl.mesh.nnum[0]
mapdl.nsel("S", "NODE", vmin=single_node, vmax=single_node)
mapdl.f("ALL", "FX", 1000)

mapdl.allsel(mute=True)

mapdl.run("/SOLU")
mapdl.antype("STATIC")
mapdl.solve()
mapdl.finish()

result = mapdl.result
_, stress = result.principal_nodal_stress(0)
von_mises = stress[:, -1]  # von-Mises stress is the right most column
max_stress = np.nanmax(von_mises)

mask = result.mesh.nodes[:, 0] == length

adj = width / (width - notch_depth * 2)



Run the batch and record the stress concentration

if RUN_BATCH:
k_t_exp = []
ratios = np.linspace(0.05, 0.75, 9)
print("    Ratio  : Stress Concentration (K_t)")
for ratio in ratios:
stress_con = compute_stress_con(ratio)
print("%10.4f : %10.4f" % (ratio, stress_con))
k_t_exp.append(stress_con)


## Analytical Solution#

Stress concentrations are often obtained by referencing tabular results or polynominal fits for a variety of geometries. According to Roark’s Formulas for Stress and Strain (Warren C. Young and Richard G. Budynas, Seventh Edition, McGraw-Hill) the analytical equation for two U notches in a thin plate in uniaxial tension:

$K_t = C_1 + C_2 \left(\dfrac{2h}{D}\right) + C_3 \left(\dfrac{2h}{D}\right)^2 + C_4 \left(\dfrac{2h}{D}\right)^3$

where:

$\begin{split}\begin{array}{c|c|c} & 0.1 \leq h/r \leq 2.0 & 2.0 \leq h/r \leq 50.0 \\ \hline C_1 & 0.85 + 2.628 \sqrt{h/r} - 0.413 h/r & 0.833 + 2.069 \sqrt{h/r} - 0.009 h/r \\ C_2 & -1.119 - 4.826 \sqrt{h/r} + 2.575 h/r & 2.732 - 4.157 \sqrt{h/r} + 0.176 h/r \\ C_3 & 3.563 - 0.514 \sqrt{h/r} - 2.402 h/r & -8.859 + 5.327 \sqrt{h/r} - 0.32 h/r \\ C_4 & -2.294 + 2.713 \sqrt{h/r} + 0.240 h/r & 6.294 - 3.239 \sqrt{h/r} + 0.154 h/r \end{array}\end{split}$

Where:

• $$K_t$$ is the stress concentration

• $$r$$ is the radius of the notch

• $$h$$ is the notch depth

• $$D$$ is the width of the plate

In this example the ratio is given as $$2h/D$$.

These formulas are converted in the following function:

def calc_teor_notch(ratio):
notch_depth = ratio * width / 2
h = notch_depth
D = width

if 0.1 <= h / r <= 2.0:
c1 = 0.85 + 2.628 * (h / r) ** 0.5 - 0.413 * h / r
c2 = -1.119 - 4.826 * (h / r) ** 0.5 + 2.575 * h / r
c3 = 3.563 - 0.514 * (h / r) ** 0.5 - 2.402 * h / r
c4 = -2.294 + 2.713 * (h / r) ** 0.5 + 0.240 * h / r
elif 2.0 <= h / r <= 50.0:
c1 = 0.833 + 2.069 * (h / r) ** 0.5 - 0.009 * h / r
c2 = 2.732 - 4.157 * (h / r) ** 0.5 + 0.176 * h / r
c3 = -8.859 + 5.327 * (h / r) ** 0.5 - 0.32 * h / r
c4 = 6.294 - 3.239 * (h / r) ** 0.5 + 0.154 * h / r

return c1 + c2 * (2 * h / D) + c3 * (2 * h / D) ** 2 + c4 * (2 * h / D) ** 3


which is used later to calculate the concentration factor for the given ratios:

if RUN_BATCH:
print("    Ratio  : Stress Concentration (K_t)")
k_t_anl = []
for ratio in ratios:
stress_con = calc_teor_notch(ratio)
print("%10.4f : %10.4f" % (ratio, stress_con))
k_t_anl.append(stress_con)


## Analytical Comparison#

As shown in the following plot, MAPDL matches the known tabular result for this geometry remarkably well using PLANE183 elements. The fit to the results may vary depending on the ratio between the height and width of the plate.

if RUN_BATCH:
plt.plot(ratios, k_t_anl, label=r"$K_t$ Analytical")
plt.plot(ratios, k_t_exp, label=r"$K_t$ ANSYS")
plt.legend()
plt.show()


stop mapdl

mapdl.exit()


Total running time of the script: ( 0 minutes 7.362 seconds)

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